Maths Olympiad Prep

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Algebra Difficulty 2.1 Junior Prove it Canada

IMG0 In a sequence with six terms, each term
after the second is the sum of the previous two terms. If the fourth
term is 1313 and the sixth term is 3636, what is the first term?Figure 1 For some real number r0r \neq 0, the sequence 5r5r, 5r25r^2, 5r35r^3 has the property that the second term plus the third term equals the square of the first term. What is the value of rr?Figure 2 Jimmy wrote four tests last week. The average of his marks on the first, second and third tests was 6565. The average of his marks on the second, third and fourth tests was 8080. His mark on the fourth test was 22 times his mark on the first test.
Determine his mark on the fourth test.

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Solution

Since y=r(x3)(xr)y = r(x - 3)(x - r) passes through (0,48)(0,48), then 48=r(03)(0r)48 = r(0-3)(0-r). Thus, 48=3r248 = 3r^2 and so r2=16r^2 = 16 or r=±4r = \pm 4.
With 13%13\% sales tax on an item whose price is $B\$B, the total cost is $(1.13B)\$(1.13B). With 5%5\% sales tax on an item whose price is $B\$B, the total cost is $(1.05B)\$(1.05B). From the given information $$(1.13B) -
$(1.05B) = $24or or 1.13B - 1.05B = 24$.

Therefore, 0.08B=240.08B = 24, which gives B=300B = 300. Alternatively, we could note that the difference in total prices is the difference in the amount of tax paid. This is the difference between 13%13\% of the original price and 5%5\% of the original price; this difference is equal to 8%8\% of the original price. If 8%8\% of the original price is equal to $24\$24, then 1%1\% of the original price is equal to $3\$3 and so the original price is $$3 ×\times 100 =
$300.When. When n=1,, f(2n) = (f(n))^2becomes becomes f(2) = (f(1))^2.Since. Since f(1) = 3,then, then f(2) = 3^2 = 9.When. When m=1,, f(2m+1) = 3f(2m)becomes becomes f(3) = 3f(2).Since. Since f(2) = 9,then, then f(3) = 3 \cdot 9 = 27.When. When n=2,, f(2n) = (f(n))^2becomes becomes f(4) = (f(2))^2.Since. Since f(2) = 9,then, then f(4) = 9^2 = 81.Therefore,. Therefore, f(2) + f(3) + f(4) = 9 + 27 + 81
= 117$.

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