Library / CEMC Fermat / 108 of 566
CEMC Fermat, 2024 Algebra Difficulty 1.0 Junior Find the answer Canada
The value of 3 ( 5 3 − 1 3 ) 3\left(\frac 53-\frac 13\right) 3 ( 3 5 − 3 1 ) is
Pick one
A 1 1 1 B 2 2 2 C 3 3 3 D 4 4 4 E 6 6 6
Solution Calculating, 3 ( 5 3 − 1 3 ) = 3 ⋅ 5 3 − 3 ⋅ 1 3 = 5 − 1 = 4 3 \left(\frac{5}{3}-\frac{1}{3}\right) = 3 \cdot \frac{5}{3} - 3 \cdot \frac{1}{3} = 5 - 1 = 4 3 ( 3 5 − 3 1 ) = 3 ⋅ 3 5 − 3 ⋅ 3 1 = 5 − 1 = 4 .
Alternatively, 3 ( 5 3 − 1 3 ) = 3 ⋅ 4 3 = 4 3 \left(\frac{5}{3}-\frac{1}{3}\right) = 3 \cdot \frac{4}{3} = 4 3 ( 3 5 − 3 1 ) = 3 ⋅ 3 4 = 4 .
← Previous Browse the library Next →
Want a route through all this instead of an archive?
The track
puts 2,604 problems in a working order, from Junior Challenge level to the IMO shortlist.
Source: CEMC, University of Waterloo ,
licensed CC-BY-NC-4.0 .
Statement reproduced verbatim; metadata (topic, difficulty) added by this project.