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CEMC Pascal, 2014

Number theory Difficulty 1.4 Junior Find the answer Canada

In the subtraction shown, XX and YY are digits. What is the value of X+YX+Y?
Figure 0

Pick one

Solution

We rearrange the given subtraction to create the addition statement 45+8Y=1X245+8Y=1X2.

Next, we consider the units digits.

From the statement, the sum 5+Y5+Y has a units digit of 2. This means that Y=7Y=7. This is the only possibility. Therefore, we have 45+87=1X245+87 = 1X2.

But 45+87=13245+87=132, so X=3X=3.

Therefore, X+Y=3+7=10X+Y=3+7=10.

(We can check that 132−87=45132 - 87 = 45, as required.)

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