Library / /43 of 472

, 2005

Algebra Difficulty 1.0 Junior Find the answer Canada

The sum of the first 2005 terms of the sequence $1, 2, 3, 4, 1, 2, 3, 4, \ldots$ is

(A) $5011$ (B) $5110$ (C) $5020$ (D) $5010$ (E) $501$

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project. Solutions are the publisher's, linked not copied.