Library / /46 of 472

, 2005

Algebra Difficulty 1.0 Junior Find the answer Canada

If $\sqrt{4 + 9 + x^2} = 7$ , then a possible value for $x$ is

(A) $6$ (B) $2$ (C) $4$ (D) $36$ (E) $0$

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project. Solutions are the publisher's, linked not copied.