Maths Olympiad Prep

Library / /397 of 472

, 2005

Geometry Difficulty 3.0 AMC 10/12 Find the answer Canada

In triangle ABCABC, if AB=AC=x+1AB = AC = x + 1 and BC=2x−2BC = 2x - 2, where x>1x > 1, then the area of the triangle is always equal to

(A) (x−1)2x2+2(x - 1)\sqrt{2x^2 + 2} (B) 2(x−1)2(x - 1) (C) 12(x+1)2\dfrac{1}{2}(x + 1)^2 (D) (x+1)(x−1)(x + 1)(x - 1) (E) 2(x−1)x2(x - 1)\sqrt{x}

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project. Solutions are the publisher's, linked not copied.