, 2016

Since $128 = 2^7$, its positive divisors are $$2^0=1 \qquad 2^1=2 \qquad 2^2=4 \qquad 2^3=8 \qquad 2^4=16 \qquad 2^5=32 \qquad 2^6=64 \qquad 2^7=128$$ Of these, the integers $1, 4, 16, 64$ are perfect squares, which means that 128 has three positive divisors that are perfect squares larger than 1.