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, 2003

Algebra Difficulty 1.0 Junior Find the answer Canada

The value of $1.000+0.101+0.011+0.001$ is

(A) $1.112$ (B) $1.113$ (C) $1.111$ (D) $1.1111$ (E) $1.101$

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project. Solutions are the publisher's, linked not copied.