At the beginning of the first day, a box contains 1 black ball, 1
gold ball, and no other balls. At the end of each day, for each gold
ball in the box, 2 black balls and 1 gold ball are added to the box;
this means that at the end of the first day, there are 5 balls in the
box. If no balls are removed from the box, how many balls are in the box
at the end of the seventh day?
, 2022
Pick one
Solution
At the beginning of the first day, the box contains 1 black ball
and 1 gold ball.
At the end of the first day, 2 black balls and 1 gold ball are added, so
the box contains 3 black balls and 2 gold balls.
At the end of the second day, $2 2 =
42 1 =
2$ gold balls are added, so the box contains 7 black balls and 4
gold balls.
Continuing in this way, we find the following numbers of balls:
End of Day #
Black Balls
Gold Balls
2
7
4
3
$7 + 4
2 = 15$
$4 + 4 =
8$
4
$15 + 8
2 = 31$
$8 + 8 =
16$
5
$31 + 16
2 = 63$
$16 + 16 =
32$
6
$63 + 32
2 = 127$
$32 + 32 =
64$
7
$127 + 64
2 = 255$
$64 + 64 =
128$
At the end of the 7th day, there are thus balls in the box.
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