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, 2011

Algebra Difficulty 1.0 Junior Find the answer Canada

The largest number in the list $\left\{\frac{3}{10}, \frac{9}{20}, \frac{12}{25}, \frac{27}{50}, \frac{49}{100}\right\}$ is

(A) $\frac{3}{10}$ (B) $\frac{9}{20}$ (C) $\frac{12}{25}$ (D) $\frac{27}{50}$ (E) $\frac{49}{100}$

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project. Solutions are the publisher's, linked not copied.