Library / /94 of 475

, 2003

Algebra Difficulty 1.0 Junior Find the answer Canada

If $n$ is any integer, $n + 3$ , $n - 9$ , $n - 4$ , $n + 6$ , and $n - 1$ are also integers. If $n + 3$ , $n - 9$ , $n - 4$ , $n + 6$ , and $n - 1$ are arranged from smallest to largest, the integer in the middle is

(A) $n+3$ (B) $n-9$ (C) $n-4$ (D) $n+6$ (E) $n-1$

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project. Solutions are the publisher's, linked not copied.