CEMC Fermat, 2003

Geometry Difficulty 2.0 Junior Find the answer Canada

In the diagram, $D$ is the point on $BC$ so that $AD$ is perpendicular to $BC$ . The slope of $AD$ is

(A) $\frac{3}{11}$ (B) $1$ (C) $-\frac{15}{11}$ (D) $\frac{2}{7}$ (E) $\frac{2}{5}$

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