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Algebra Difficulty 1.4 Junior Find the answer Canada

What number goes in the box so that $\dfrac{28}{32}+\dfrac{1}{\square}=1$ ?

Pick one

Solutions — 2

Solution 1

Since $\dfrac{28}{32}+\dfrac{1}{\Box}=1$ and
$\dfrac{28}{32}+\dfrac{4}{32}=\dfrac{32}{32}=1$ ,
then $\dfrac{1}{\square}=\dfrac{4}{32}$ .

Reducing $\dfrac{4}{32}$ to lowest
terms, we get $\dfrac{4}{32}=\dfrac{1}{8}$ , and so the
number that goes in the box is $8$ .

Solution 2

Since $\dfrac{28}{32}+\dfrac{1}{\Box}=1$ and
$\dfrac{28}{32}+\dfrac{4}{32}=\dfrac{32}{32}=1$ ,
then $\dfrac{1}{\square}=\dfrac{4}{32}$ .

Reducing $\dfrac{4}{32}$ to lowest
terms, we get $\dfrac{4}{32}=\dfrac{1}{8}$ , and so the
number that goes in the box is $8$ .

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.