CEMC Fermat, 2004

Geometry Difficulty 3.0 AMC 10/12 Find the answer Canada

In the diagram, $ABCD$ is a rectangle and point $E$ lies on $AB$ . Triangle $DEC$ has $\angle DEC=90^{\circ}$ , $DE=3$ and $EC=4$ . The length of $AD$ is

(A) $2.6$ (B) $2.4$ (C) $2.8$ (D) $1.8$ (E) $3.2$

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