Solution 1
Since ∠BCD is a straight
angle, then $∠ ACB = 180°−∠
ACD = 180°−150°=30°$.
Since the measures of the angles in △ABC add to 180°, then $x°+90°+30°=180°andsox = 180 - 120 =
60$.
Solution 2
Since the measures of the angles in △ABC add to 180°, then ∠ACB=180°−∠ABC−∠BAC=180°−90°−x°=90°−x°
Since ∠BCD=180°, then
∠ACB+∠ACD(90°−x°)+150°240−x=180°=180°=180 and so x=60.