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, 2011

Algebra Difficulty 1.0 Junior Find the answer Canada

$\dfrac{2 + 3 \times 6}{23 + 6}$ is equal to

(A) $1$ (B) $\frac{11}{29}$ (C) $\frac{36}{29}$ (D) $\frac{20}{29}$ (E) $\frac{5}{23}$

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project. Solutions are the publisher's, linked not copied.