Lonnie rests for 30 s between the 1st and 2nd sprints, the 2nd
and 3rd sprints, and so on up to and including the 23rd and 24th
sprints.
Thus, Lonnie takes the 30 s rest 23 times.
Since Lonnie sprints at a constant speed of 8 m/s, then it takes
Lonnie 200 m}}{8
m/s}}=25$ s to sprint 200 m.
Lonnie completes 24 such sprints, and so his time spent sprinting is
24×25 s=600 s.
Lonnie also takes 23 rests, each of length 30 s, and so his time spent
resting is $23×30 s=690
s}$.
On Monday, Lonnie’s total practice time is thus 600 s+690 s=1290
s.
Solution 1
On Tuesday, each of Lonnie’s 240 m sprints takes 8 m/s240 m=30
s, and so Lonnie spends $20×30 s=600 s}$ sprinting.
Lonnie rests 19 times, and so he rests for a total of 19×30 s=570 s.
On Tuesday, Lonnie’s total practice time is thus 600 s+570 s=1170 s, and
so Tuesday’s practice takes 1290−1170=120 fewer seconds compared to
Monday’s practice.
Solution 2
On Monday, Lonnie sprints $24 ×200 m}=4800$ m.
On Tuesday, Lonnie also sprints $20 ×240 m}=4800$ m.
Since Lonnie sprints at the same constant speed on both days, then he
spends the same amount of time sprinting on each of the two days.
Thus, the difference between the length of time that Lonnie practices on
the two days is the difference between the time that he spends resting
between sprints.
Lonnie rests 23 times on Monday, and he rests 19 times on Tuesday.
Since he rests 4 more times on Monday than he does on Tuesday, then
Tuesday’s practice takes $4×
30=120$ fewer seconds compared to Monday’s practice.