Maths Olympiad Prep

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CEMC Cayley, 2024

Geometry Difficulty 2.1 Junior Find the answer Canada

In △ABC\triangle ABC, points
EE and FF are on ABAB and BCBC, respectively, such that AE=BFAE=BF and BE=CFBE=CF.

Figure 0

If ∠BAC=70°\angle BAC = 70\degree, the
measure of ∠ABC\angle ABC is

Pick one

Solution

Since AE=BFAE = BF and BE=CFBE = CF, then AB=AE+BE=BF+CF=BCAB = AE + BE = BF + CF = BC.

Therefore, △ABC\triangle ABC is
isosceles with ∠BAC=∠BCA=70°\angle BAC = \angle BCA = 70\degree.

Since the sum of the angles in △ABC\triangle ABC is 180°180\degree, then
∠ABC=180°−∠BAC−∠BCA=180°−70°−70°=40°\angle ABC = 180\degree - \angle BAC - \angle BCA = 180\degree - 70\degree - 70\degree = 40\degree

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