Maths Olympiad Prep

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Geometry Difficulty 2.1 Junior Find the answer Canada

In ABC\triangle ABC, points EE and FF are on ABAB and BCBC, respectively, such that AE=BFAE=BF and BE=CFBE=CF.Figure 0If BAC=70°\angle BAC = 70\degree, the measure of ABC\angle ABC is

Pick one

Solution

Since AE=BFAE = BF and BE=CFBE = CF, then AB=AE+BE=BF+CF=BCAB = AE + BE = BF + CF = BC. Therefore, ABC\triangle ABC is isosceles with $\$\angle BAC = \angle BCA =
70°70\degree. Since the sum of the angles in

Figure for this problem\triangle
ABCis is 180°$,180\degree\$, then
ABC=180°BACBCA=180°70°70°=40°\angle ABC = 180\degree - \angle BAC - \angle BCA = 180\degree - 70\degree - 70\degree = 40\degree

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