In △ABC, points E and F are on AB and BC, respectively, such that AE=BF and BE=CF.If ∠BAC=70°, the measure of ∠ABC is
Pick one
Solution
Since AE=BF and BE=CF, then AB=AE+BE=BF+CF=BC. Therefore, △ABC is isosceles with $∠ BAC = ∠ BCA = 70°. Since the sum of the angles in
△ ABCis180°$, then ∠ABC=180°−∠BAC−∠BCA=180°−70°−70°=40°
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