Maths Olympiad Prep

Library / /69 of 472

, 1998

Algebra Difficulty 1.0 Junior Find the answer Canada

The value of 1+2+3+4+52+4+6+8+10\dfrac{1+2+3+4+5}{2+4+6+8+10} is

(A) 13\dfrac{1}{3} (B) 2.52.5 (C) 12\dfrac{1}{2} (D) 1126\dfrac{11}{26} (E) 38\dfrac{3}{8}

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project. Solutions are the publisher's, linked not copied.