CEMC Fermat, 2000

Geometry Difficulty 3.0 AMC 10/12 Find the answer Canada

In the regular hexagon $ABCDEF$ two of the diagonals, $FC$ and $BD$ , intersect at $G$ . The ratio of the area of quadrilateral $FEDG$ to the area of $\triangle BCG$ is

(A) $3\sqrt{3}:1$ (B) $4:1$ (C) $6:1$ (D) $2\sqrt{3}:1$ (E) $5:1$

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