Library / /149 of 413

, 1999

Algebra Difficulty 1.0 Junior Find the answer Canada

If $\frac{n+1999}{2} = -1$ , then the value of $n$ is

(A) $-2001$ (B) $-2000$ (C) $-1999$ (D) $-1997$ (E) $1999$

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project. Solutions are the publisher's, linked not copied.