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, 2005

Algebra Difficulty 1.0 Junior Find the answer Canada

If $a = \dfrac{1}{2}$ and $b = \dfrac{2}{3}$ , then $\dfrac{6a + 18b}{12a + 6b}$ equals

(A) $9$ (B) $7$ (C) $10$ (D) $6$ (E) $\dfrac{3}{2}$

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project. Solutions are the publisher's, linked not copied.