, 1999

If $a_1 = \frac{1}{1-x}$, $a_2 = \frac{1}{1-a_1}$, and $a_n = \frac{1}{1-a_{n-1}}$, for $n \ge 2$, $x \ne 1$ and $x \ne 0$, then $a_{107}$ is

(A) $\frac{1}{1-x}$ (B) $x$ (C) $-x$ (D) $\frac{x-1}{x}$ (E) $\frac{1}{x}$