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CEMC Gauss (Grade 8), 2003

Algebra Difficulty 2.0 Junior Find the answer Canada

A different digit is inserted into each of the two boxes to make the equation $15.2+1.52+0.15\square+\square.128=20$ true. The sum of the digits in the two boxes is

(A) $5$ (B) $6$ (C) $7$ (D) $8$ (E) $9$

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