Maths Olympiad Prep

Library / /332 of 413

, 2003

Algebra Difficulty 2.0 Junior Find the answer Canada

A different digit is inserted into each of the two boxes to make the equation 15.2+1.52+0.15+.128=2015.2+1.52+0.15\square+\square.128=20 true. The sum of the digits in the two boxes is

(A) 55 (B) 66 (C) 77 (D) 88 (E) 99

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project. Solutions are the publisher's, linked not copied.