, 2023

Since $a = \dfrac{1}{n}$ where
$n$ is a positive integer with $\text{n gt; 1}$, then $\text{0 lt; a lt; 1}$ and $\text{1 a = n gt; 1}$.

Thus, $\text{0 lt; a lt; 1 lt; 1 a}$, which eliminates choices (D) and (E).

Since $\text{0 lt; a lt; 1}$, then $a^2$ is positive and $\text{a 2 lt; a}$, which eliminates choices (A)
and (C).

Thus, $\text{0 lt; a 2 lt; a lt; 1 lt; 1 a}$, which tells us that (B) must be correct.