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Algebra Difficulty 1.3 Junior Find the answer Canada

The average of $\dfrac{1}{8}$ and $\dfrac{1}{6}$ is

Pick one

Solution

The average of $\dfrac{1}{8}$ and $\dfrac{1}{6}$ is $\dfrac{\dfrac{1}{8}+\dfrac{1}{6}}{2} = \dfrac{\dfrac{3}{24}+\dfrac{4}{24}}{2} = \dfrac{1}{2} \times \dfrac{7}{24} = \dfrac{7}{48}$ .

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.