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KöMaL problem A, 2014

Algebra Difficulty 7.0 National Olympiad, round 2 Prove it Hungary

Let a1,a2,…,ana_1,a_2,\dots,a_n and b1,b2,…,bnb_1,b_2,\dots,b_n be complex numbers satisfying Imaj≥1\mathop{\rm Im} a_j\ge 1 and Imbj≤−1\mathop{\rm Im} b_j\le -1 (j=1,2,…,nj=1,2,\dots,n), and let f(z)=(z−a1)(z−a2)…(z−an)(z−b1)(z−b2)…(z−bn)f(z) = \frac{(z-a_1)(z-a_2)\dots (z-a_n)}{(z-b_1)(z-b_2)\dots (z-b_n)}. Prove that the function f′(z)f'(z) has no root in the set ∣Imz∣<1|\mathop{\rm Im}z|<1.
(5 pont)

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