Maths Olympiad Prep

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, 2014

Algebra Difficulty 7.0 National Olympiad, round 2 Prove it Hungary

Let a1,a2,,ana_1,a_2,\dots,a_n and b1,b2,,bnb_1,b_2,\dots,b_n be complex numbers satisfying Imaj1\mathop{\rm Im} a_j\ge 1 and Imbj1\mathop{\rm Im} b_j\le -1 (j=1,2,,nj=1,2,\dots,n), and let f(z)=(za1)(za2)(zan)(zb1)(zb2)(zbn)f(z) = \frac{(z-a_1)(z-a_2)\dots (z-a_n)}{(z-b_1)(z-b_2)\dots (z-b_n)}. Prove that the function f(z)f'(z) has no root in the set Imz<1|\mathop{\rm Im}z|<1.
(5 pont)

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