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KöMaL problem A, 2015 Algebra Difficulty 6.0 National Olympiad Prove it Hungary
Let p ( x ) p(x) p ( x ) be a polynomial of degree at most n n n such that ∣ p ( x ) ∣ ≤ 1 x \big|p(x)\big|\le\frac{1}{\sqrt{x}} p ( x ) ≤ x 1 for 0 < x ≤ 1 0<x\le 1 0 < x ≤ 1 . Prove that ∣ p ( 0 ) ∣ ≤ 2 n + 1 \big|p(0)\big|\le 2n+1 p ( 0 ) ≤ 2 n + 1 . (5 pont)
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