AlgebraDifficulty 4.9AIMEFind the answerUnited States
Problem: Let x and y be positive real numbers and θ an angle such that θ=2πn for any integer n. Suppose xsinθ=ycosθ and x4cos4θ+y4sin4θ=x3y+y3x97sin2θ Compute yx+xy.
A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.
Solution
Solution: From the first relation, there exists a real number k such that x=ksinθ and y=kcosθ. Then we have sin4θcos4θ+cos4θsin4θ=sinθcosθ(cos2θ+sin2θ)194sinθcosθ=194 Notice that if t=yx+xy then (t2−2)2−2=sin4θcos4θ+cos4θsin4θ=194 and so t=4.
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