For each positive integer n the function fn:[0,n]→R is defined by fn(x)=arctg(⌊x⌋). Prove that fn is a Riemann integrable function
and find n→∞limn1∫0nfn(x)dx.
Solution
The function fn is locally constant, hence Riemann integrable.
Next, we have ∫0nfn(x)dx=i=0∑n−1∫ii+1fn(i)dx=i=0∑n−1arctani. Applying Stolz-Cesàro theorem, we obtain n→∞limnarctan1+arctan2+⋯+arctann=n→∞limarctann=2π.
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