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Belarusian Mathematical Olympiad

Combinatorics Difficulty 5.3 AIME, harder Prove it Belarus

Each cell of an n×nn \times n table is filled with one of the two signs: «+» and «-». For each kk from 11 to nn the amount of pluses in the first kk rows is greater than the amount of minuses in the first kk columns.
Find the maximal possible number of minuses in the table.

Solution

Answer: [n2−12]\left[ \frac{n^2 - 1}{2} \right].

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