Let n be a positive integer. Prove that the interval In=(21+8n+1,21+8n+9) does not contain any integer.
Solution
Suppose that we have 21+8n+1<x<21+8n+9 for some positive integer x. Then 8n+1<2x−1<8n+9 hence 8n+1<4x2−4x+1<8n+9. It follows 2n<x2−x<2n+2, that is x2−x=2n+1, not possible since x2−x is an even integer.
Want a route through all this instead of an archive? The track
puts 2,000 problems in a working order, from AMC 10 level to the IMO shortlist.
Source: MathNet,
licensed CC-BY-4.0.
Statement and solution reproduced as published; topic and difficulty added by this site.