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Algebra Difficulty 3.8 AMC 10/12 Find the answer Italy

Problem:

Two numbers aa and bb are such that 3a+bab=2\frac{3a+b}{a-b}=2. What is the value of a3b3\frac{a^{3}}{b^{3}}?

Pick one

Solution

Solution:

The answer is (A)(\mathbf{A}). We have 3a+b=2a2b3a+b=2a-2b, so a=3ba=-3b, and therefore a3b3=(3)3=27\frac{a^{3}}{b^{3}}=(-3)^{3}=-27.

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Source: MathNet, licensed CC-BY-4.0. Statement translated into English from the original; metadata (topic, difficulty) added by this project.