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Geometry Difficulty 5.1 AIME, harder Prove it Saudi Arabia

Let (O1)(O_{1}), (O2)(O_{2}) be given two circles intersecting at AA and BB. The tangent lines of (O1)(O_{1}) at AA, BB intersect at OO. Let II be a point on the circle (O1)(O_{1}) but outside the circle (O2)(O_{2}). The lines IAIA, IBIB intersect circle (O2)(O_{2}) at CC, DD. Denote by MM the midpoint of CDCD. Prove that II, MM, OO are collinear.

Solution

Denote NN as the midpoint of ABAB. Because AA, BB, CC, DD belong to the same circle, then we have
IABIDC. \triangle IAB \sim \triangle IDC.
Since MM is the midpoint of CDCD and NN is the midpoint of ABAB then IMIM, ININ are isogonal conjugate with respect to the angle CID\angle CID.

In the other hand, OO is the intersection of two tangent lines of (O2)(O_{2}) at AA, BB, then IOIO is the symmedian of triangle IABIAB. It means IOIO, ININ are isogonal conjugate with respect to AIB\angle AIB.

Hence, II, MM, OO are collinear.

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