AlgebraDifficulty 4.2AIMEFind the answerPhilippines
Problem: The polynomial p(x)=x2−3x+1 has zeros r and s and a quadratic polynomial q(x) has leading coefficient 1 and zeros r3 and s3. Find q(1).
A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.
Solution
Solution: We have r+s=3 and rs=1. By Vieta's formulas, we compute r3+s3=(r+s)3−3rs(r+s)=27−3(1)(3)=18 and r3s3=1. Thus, we obtain q(x)=(x−r3)(x−s3)=x2−(r3+s3)x+r3s3=x2−18x+1. Hence, we get q(1)=−16.
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