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Algebra Difficulty 3.8 AMC 10/12 Find the answer Slovenia

Let mm and nn be positive integers, such that 19m4919 \le m \le 49, 51n10151 \le n \le 101. What is the greatest possible value of the expression n+mnm\frac{n+m}{n-m}?

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Solution

We have n+mnm=nm+2mnm=1+2mnm\frac{n+m}{n-m} = \frac{n-m+2m}{n-m} = 1 + 2\frac{m}{n-m}, so the value is maximal when nm=2n-m = 2 and m=49m = 49. Then, the value is 5050.

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