Find all non-zero integers a, different from 4, such that a−4a+a2 is an integer as well.
Solution
If a−4a+a2=a(a−4)a2+2a−8 is an integer, then a(a−4) divides a2+2a−8. So, a divides a2+2a−8, and a divides 8. All integer divisors of 8 different from 4 are 1, 2, 8, −1, −2, −4 and −8. We check all seven cases and see that the value of the expression is an integer only when a=2 or a=−4.
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Source: MathNet,
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