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Algebra Difficulty 5.3 AIME, harder Prove it North Macedonia

Four boys Andrej, Bojan, Vasko and Goce are collecting post stamps. Andrej has as many post stamps as Bojan and Vasko have together. Goce has five times less post stamps than Andrej, and Bojan has four times more post stamps than Vasko. If they together have 5016 post stamps, how many post stamps each of the four boys has?

Solution

Let AA, BB, VV and GG be the numbers of post stamps that Andrej, Bojan, Vasko and Goce have correspondingly. According to the first condition of the problem we obtain A=B+VA = B + V, A=5GA = 5G, B=4VB = 4V. Then we have that A=B+V=4V+V=5VA = B + V = 4V + V = 5V. But A=5GA = 5G so we get that V=GV = G. Then according to the second condition of the problem we obtain A+B+V+G=5016A + B + V + G = 5016, 5V+4V+V+V=50165V + 4V + V + V = 5016. Hence 11V=501611V = 5016, V=456V = 456. Now we get that G=456G = 456, A=5456=2280A = 5 \cdot 456 = 2280 and B=4456=1824B = 4 \cdot 456 = 1824. So Andrej has 2280 post stamps, Bojan has 1824 and Vasko and Goce have 456 post stamps each.

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Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.