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Algebra Difficulty 5.0 AIME Prove it United States
Problem:
Let x, y, and z be distinct real numbers that sum to 0. Find the maximum possible value of
x2+y2+z2xy+yz+zx.
Solution
Solution:
−1/2
Note that 0=(x+y+z)2=x2+y2+z2+2xy+2yz+2zx. Rearranging, we get that xy+yz+zx=−21(x2+y2+z2), so that in fact the quantity is always equal to −1/2.
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