Maths Olympiad Prep

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Algebra Difficulty 5.0 AIME Prove it United States

Problem:
Let xx, yy, and zz be distinct real numbers that sum to 00. Find the maximum possible value of
xy+yz+zxx2+y2+z2. \frac{x y + y z + z x}{x^{2} + y^{2} + z^{2}}.

Solution

Solution:
1/2-1/2

Note that 0=(x+y+z)2=x2+y2+z2+2xy+2yz+2zx0 = (x + y + z)^2 = x^2 + y^2 + z^2 + 2 x y + 2 y z + 2 z x. Rearranging, we get that xy+yz+zx=12(x2+y2+z2)x y + y z + z x = -\frac{1}{2}(x^2 + y^2 + z^2), so that in fact the quantity is always equal to 1/2-1/2.

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Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.