Maths Olympiad Prep

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Algebra Difficulty 5.2 AIME, harder Prove it South Africa

If xx and yy are positive real numbers such that
2x+y=13 and 8x+9y=35, \sqrt{2x} + \sqrt{y} = 13 \text{ and } \sqrt{8x} + \sqrt{9y} = 35,
calculate 20x+23y20x + 23y.

Solution

The second equation can be written as 22x+3y=352\sqrt{2x} + 3\sqrt{y} = 35. Together with the first equation, we obtain a system of two linear equations in the two unknowns 2x\sqrt{2x} and y\sqrt{y}, which can easily be solved to give 2x=4\sqrt{2x} = 4 and y=9\sqrt{y} = 9. From this follows x=8x = 8 and y=81y = 81, so that 20x+23y=208+2381=202320x + 23y = 20 \cdot 8 + 23 \cdot 81 = 2023.

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