Maths Olympiad Prep

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, 2013

Number theory Difficulty 5.1 AIME, harder Prove it Slovenia

What is the greatest common divisor of the numbers 11n+411n + 4 and 7n+27n + 2, where nn is a positive integer?

Solution

The greatest common divisor of 11n+411n+4 and 7n+27n+2 also divides 7(11n+4)11(7n+2)=67(11n+4) - 11(7n+2) = 6, so it can be at most 66. If n=4n=4, then 11n+4=4811n+4 = 48 and 7n+2=307n+2 = 30, and the greatest common divisor of these two numbers is 66. Hence, the answer is 66.

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