Problem:
Show that no rectangle of the form or , where , is -tileable.
Problem:
Show that no rectangle of the form or , where , is -tileable.
Solution:
The claim is obvious for rectangles. For the others, color the first two columns black, the next two white, the next two black, etc. Each domino will contain one square of each color, so in order to be tileable, the rectangle must contain the same number of black and white squares. This is the case only when .