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HMIC, 2018

Combinatorics Difficulty 5.6 AIME, harder Prove it United States

Problem:

Consider a finite set of points T∈RnT \in \mathbb{R}^n contained in the nn-dimensional unit ball centered at the origin, and let XX be the convex hull of TT. Prove that for all positive integers kk and all points x∈Xx \in X, there exist points t1,t2,…,tk∈Tt_1, t_2, \ldots, t_k \in T, not necessarily distinct, such that their centroid
t1+t2+⋯+tkk \frac{t_1 + t_2 + \cdots + t_k}{k}
has Euclidean distance at most 1k\frac{1}{\sqrt{k}} from xx.

(The nn-dimensional unit ball centered at the origin is the set of points in Rn\mathbb{R}^n with Euclidean distance at most 1 from the origin. The convex hull of a set of points T∈RnT \in \mathbb{R}^n is the smallest set of points XX containing TT such that each line segment between two points in XX lies completely inside XX.)

Solution

Solution:

By the definition of convex hull, we can write x=∑i=1mλizix=\sum_{i=1}^{m} \lambda_{i} z_{i}, where each zi∈Tz_{i} \in T, each λi≥0\lambda_{i} \geq 0 and ∑i=1mλi=1\sum_{i=1}^{m} \lambda_{i}=1. Consider then a random variable ZZ that takes on value ziz_{i} with probability λi\lambda_{i}. We have E[Z]=x\mathbb{E}[Z]=x. Let Zˉ=1k∑i=1kZi\bar{Z}=\frac{1}{k} \sum_{i=1}^{k} Z_{i}, where each ZiZ_{i} is an independent copy of ZZ. Then we wish to compute
Var⁡[Zˉ]=1k2∑i=1kVar⁡[Zi] \operatorname{Var}[\bar{Z}]=\frac{1}{k^{2}} \sum_{i=1}^{k} \operatorname{Var}\left[Z_{i}\right]
Finally, we have
Var⁡[Zi]=E[∥Zi−x∥2]=E[∥Zi∥2]−x2≤E[∥Zi∥2]≤1 \operatorname{Var}\left[Z_{i}\right]=\mathbb{E}\left[\left\|Z_{i}-x\right\|^{2}\right]=\mathbb{E}\left[\left\|Z_{i}\right\|^{2}\right]-x^{2} \leq \mathbb{E}\left[\left\|Z_{i}\right\|^{2}\right] \leq 1
The second equality follows from the identity Var⁡[X]=E[X2]−E[X]2\operatorname{Var}[X]=\mathbb{E}\left[X^{2}\right]-\mathbb{E}[X]^{2}. Now, we know that
E[∥x−1k∑i=1kZi∥2]=Var⁡[Zˉ]≤1k \mathbb{E}\left[\left\|x-\frac{1}{k} \sum_{i=1}^{k} Z_{i}\right\|^{2}\right]=\operatorname{Var}[\bar{Z}] \leq \frac{1}{k}
Thus, there must exist some realization of xix_{i} of the ZiZ_{i} such that
∥x−1k∑i=1kxi∥2≤1k \left\|x-\frac{1}{k} \sum_{i=1}^{k} x_{i}\right\|^{2} \leq \frac{1}{k}
and we are done.

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