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HMMT February, 2018

Algebra Difficulty 4.8 AIME Find the answer United States

Problem:

Randall proposes a new temperature system called Felsius temperature with the following conversion between Felsius {}∘E\{ \}^{\circ} E, Celsius {}∘C\{ \}^{\circ} C, and Fahrenheit {}∘F\{ \}^{\circ} F:
{}∘E=7×{}∘C5+16=7×{}∘F−809. \{ \}^{\circ} E = \frac{7 \times \{ \}^{\circ} C}{5} + 16 = \frac{7 \times \{ \}^{\circ} F - 80}{9}.
For example, 0∘C=16∘E0^{\circ} C = 16^{\circ} E. Let x,y,zx, y, z be real numbers such that x∘C=x∘Ex^{\circ} C = x^{\circ} E, y∘E=y∘Fy^{\circ} E = y^{\circ} F, z∘C=z∘Fz^{\circ} C = z^{\circ} F. Find x+y+zx + y + z.

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

Solution:

Notice that (5k)∘C=(7k+16)∘E=(9k+32)∘F(5 k)^{\circ} C = (7 k + 16)^{\circ} E = (9 k + 32)^{\circ} F, so Felsius is an exact average of Celsius and Fahrenheit at the same temperature. Therefore we conclude that x=y=zx = y = z, and it is not difficult to compute that they are all equal to −40-40.

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