Let a be a complex number such that a5+a+1=0. What values can the expression a2(a−1) take on?
Solution
We have a5+a+1=(a5−a4)+(a4−a3)+(a3−a2)+a2+a+1=(a2+a+1)(a3−a2+1). If a2+a+1=0, then a2(a−1)=−(a+1)(a−1)=1−a2=a+2. Since a=2−1±i3, it follows that a2(a−1)=23±23i. If a3−a2+1=0, then a2(a−1)=a3−a2=−1. Therefore, the observed expression can take on values −1,23,23i and 23−23i.
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Source: MathNet,
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