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Algebra Difficulty 3.8 AMC 10/12 Find the answer China

Suppose that A={1,2,3}A = \{1, 2, 3\}, B={2x+yx,yA,x<y}B = \{2x + y \mid x, y \in A, x < y\}, C={2x+yx,yA,x>y}C = \{2x + y \mid x, y \in A, x > y\}. Then the sum of all the elements of BCB \cap C is ______.

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

By enumeration, we get B={4,5,7}B = \{4, 5, 7\}, C={5,7,8}C = \{5, 7, 8\}. Thus, BC={5,7}B \cap C = \{5, 7\}. Therefore, the sum of all the elements of BCB \cap C is 5+7=125 + 7 = 12. \square

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Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.