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Philippine Mathematical Olympiad

Algebra Difficulty 5.2 AIME, harder Prove it Philippines

Problem:

We say that the constant aa is a fixed point of a function ff if f(a)=af(a)=a. Find all values of cc such that f(x)=x2−2f(x)=x^{2}-2 and g(x)=2x2−cg(x)=2x^{2}-c share a common fixed point.

Solution

Solution:

Note that if f(x)=xf(x)=x, then x2−x−2=0x^{2}-x-2=0, or (x−2)(x+1)=0(x-2)(x+1)=0. Thus, the fixed points of ff are 22 and −1-1, and so we wish for either of these to be a fixed point of gg.

If 22 is a fixed point of gg, we must have g(2)=2=8−cg(2)=2=8-c, and so c=6c=6.

If −1-1 is a fixed point of gg, then 2−c=−12-c=-1, and c=3c=3.

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