Maths Olympiad Prep

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Combinatorics Difficulty 5.0 AIME Prove it United States

Problem:

For any finite set SS, let f(S)f(S) be the sum of the elements of SS (if SS is empty then f(S)=0f(S)=0). Find the sum over all subsets EE of SS of f(E)f(S)\frac{f(E)}{f(S)} for S={1,2,,1999}S=\{1,2, \ldots, 1999\}.

Solution

Solution:

An nn element set has 2n2^{n} subsets, so each element of SS appears in 219982^{1998} subsets EE, so our sum is 219981+2++19991+2++1999=219982^{1998} \cdot \frac{1+2+\ldots+1999}{1+2+\ldots+1999} = 2^{1998}.

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