Maths Olympiad Prep

Library / Harvard-MIT Math Tournament /52 of 83

Harvard-MIT Math Tournament

Combinatorics Difficulty 5.0 AIME Prove it United States

Problem:

For any finite set SS, let f(S)f(S) be the sum of the elements of SS (if SS is empty then f(S)=0f(S)=0). Find the sum over all subsets EE of SS of f(E)f(S)\frac{f(E)}{f(S)} for S={1,2,…,1999}S=\{1,2, \ldots, 1999\}.

Solution

Solution:

An nn element set has 2n2^{n} subsets, so each element of SS appears in 219982^{1998} subsets EE, so our sum is 21998⋅1+2+…+19991+2+…+1999=219982^{1998} \cdot \frac{1+2+\ldots+1999}{1+2+\ldots+1999} = 2^{1998}.

Want a route through all this instead of an archive? The track puts 2,604 problems in a working order, from Junior Challenge level to the IMO shortlist.

Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.