Maths Olympiad Prep

Library / /58 of 740

, 2012

Algebra Difficulty 4.5 AIME Find the answer United States

Problem:

Let Q(x)=x2+2x+3Q(x) = x^{2} + 2x + 3, and suppose that P(x)P(x) is a polynomial such that
P(Q(x))=x6+6x5+18x4+32x3+35x2+22x+8 P(Q(x)) = x^{6} + 6x^{5} + 18x^{4} + 32x^{3} + 35x^{2} + 22x + 8
Compute P(2)P(2).

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

Solution:

Note that Q(1)=2Q(-1) = 2. Therefore, P(2)=P(Q(1))=(1)6+6(1)5+18(1)4+32(1)3+35(1)2+22(1)+8=16+1832+3522+8=2P(2) = P(Q(-1)) = (-1)^{6} + 6(-1)^{5} + 18(-1)^{4} + 32(-1)^{3} + 35(-1)^{2} + 22(-1) + 8 = 1 - 6 + 18 - 32 + 35 - 22 + 8 = 2.

Want a route through all this instead of an archive? The track puts 2,000 problems in a working order, from AMC 10 level to the IMO shortlist.

Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.