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Algebra Difficulty 4.5 AIME Find the answer United States
Problem:
Let Q(x)=x2+2x+3, and suppose that P(x) is a polynomial such that
P(Q(x))=x6+6x5+18x4+32x3+35x2+22x+8
Compute P(2).
A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.
Solution
Solution:
Note that Q(−1)=2. Therefore, P(2)=P(Q(−1))=(−1)6+6(−1)5+18(−1)4+32(−1)3+35(−1)2+22(−1)+8=1−6+18−32+35−22+8=2.
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