By Ceva's theorem, AD, BE, CF are concurrent if and only if
sin∠EADsin∠CAD×sin∠CEBsin∠AEB×sin∠ACFsin∠ECF=1.

By the extended sine law, we have
sin∠EADsin∠CAD=DECD,sin∠CEBsin∠AEB=BCAB,sin∠ACFsin∠ECF=FAEF.
Thus, AD, BE, CF are concurrent if and only if
DECD×BCAB×FAEF=1.
This is exactly AB⋅CD⋅EF=BC⋅DE⋅FA.